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Units & Dimensions

JEE Main level, single correct, medium

32 of 149

Question 32 of 149

If $\epsilon_0$ denotes the permittivity of free space and $\Phi_{\mathrm{E}}$ is the flux of the electric field through the area bounded by the closed surface, then dimension of $\left(\epsilon_0 \frac{\mathrm{~d} \phi_{\mathrm{E}}}{\mathrm{dt}}\right)$ are that of :

Show answer and solution

Answer: (D) Electric current

We know that formula for displacement current is given by

\mathrm{id}=\varepsilon_0 \frac{\mathrm{~d} \phi_{\varepsilon}}{\mathrm{dt}}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Units & Dimensions (Dimensions), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.