Units & Dimensions

JEE Main level, single correct, medium

37 of 149

Question 37 of 149

Match the LIST-I with LIST-II
LIST-ILIST-IIA.Gravitational constantI.[LT−2]B.Gravitational potentialenergyII.[L2 T−2]C.Gravitational potentialIII.[ML2 T−2]D.Acceleration due togravityIV.[M−1 L3 T−2]\begin{array}{|l|l|l|l|}\hline & \text{LIST-I} & & \text{LIST-II} \\ \hline \text{A.} & \text{Gravitational constant} & \text{I.} & {\left[\mathrm{LT}^{-2}\right]} \\ \hline \text{B.} & \begin{array}{l} \text{Gravitational potential} \\ \text{energy} \end{array} & \text{II.} & {\left[\mathrm{L}^2 \mathrm{~T}^{-2}\right]} \\ \hline \text{C.} & \text{Gravitational potential} & \text{III.} & {\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]} \\ \hline \text{D.} & \begin{array}{l} \text{Acceleration due to} \\ \text{gravity} \end{array} & \text{IV.} & {\left[\mathrm{M}^{-1} \mathrm{~L}^3 \mathrm{~T}^{-2}\right]} \\ \hline \end{array}
Choose the correct answer from the options given below :

Show answer and solution

Answer: (A) A-IV, B-III, C-II, D-I

$\begin{aligned}
& \text { (A) } \mathrm{G}=\frac{\mathrm{Fr}^2}{\mathrm{~m}^2} \\
& {[\mathrm{G}]=\frac{\left[\mathrm{MLT}^{-2}\right]\left[\mathrm{L}^2\right]}{\left[\mathrm{M}^2\right]}=\left[\mathrm{M}^{-1} \mathrm{~L}^3 \mathrm{~T}^{-2}\right](\mathrm{IV})}
\end{aligned}$
(B)
$\begin{aligned}
& \text { P.E. }=\mathrm{mgh}=\left[\mathrm{MLT}^{-2} \mathrm{~L}\right] \\
& =\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right] \text { (III) }
\end{aligned}$
(C) Gravitational Potential =GMr=\frac{\mathrm{GM}}{\mathrm{r}}
=[M−1 L3 T−2][M][L]=[M0 L2 T−2]=[L2 T−2](II)=\frac{\left[\mathrm{M}^{-1} \mathrm{~L}^3 \mathrm{~T}^{-2}\right][\mathrm{M}]}{[\mathrm{L}]}=\left[\mathrm{M}^0 \mathrm{~L}^2 \mathrm{~T}^{-2}\right]=\left[\mathrm{L}^2 \mathrm{~T}^{-2}\right](\mathrm{II})
(D) Acceleration due to gravity =[g]=[LT−2](I)=[\mathrm{g}]=\left[\mathrm{LT}^{-2}\right](\mathrm{I})

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.

More Physics practice

JEE Main Physics practice question on Units & Dimensions (Dimensions), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.