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Units & Dimensions

JEE Main level, single correct, medium

89 of 149

Question 89 of 149

In van dar Wall equation $\left[P+\dfrac{a}{{V}^{2}}\right]\left[V-b\right]=RT;P$ is pressure, $V$ is volume, $R$ is universal gas constant and $T$ is temperature. The ratio of constants $\dfrac{a}{b}$ is dimensionally equal to :

Show answer and solution

Answer: (C) $PV$

\left(P+\dfrac{a}{{V}^{2}}\right)\left(V-b\right)=nRT

Dimensions of

b

should be equal to dimensions of

V

. Similarly, dimensions of

a

will be equal to dimensions of

P{V}^{2}

.
Therefore, dimensions of

\left[\dfrac{a}{b}\right]=\left[\dfrac{P{V}^{2}}{V}\right]=\left[PV\right]

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

JEE Main Physics practice question on Units & Dimensions (Dimensions), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

In van dar Wall equation [P+aV2][V−b]=RT;P\left[P+\dfrac{a}{{V}^{2}}\right]\left[V-b\right]=RT;P[P+V2a​][V−b]=RT;P is pressure, VVV is volume, RRR is universal gas constant and TTT is temperature. The ratio of constants ab\dfrac{a}{b}ba​ is dimensionally equal to :

JEE Main question paper PDF

More Physics practice

In van dar Wall equation $\left[P+\dfrac{a}{{V}^{2}}\right]\left[V-b\right]=RT;P$ is pressure, $V$ is volume, $R$ is universal gas constant and $T$ is temperature. The ratio of constants $\dfrac{a}{b}$ is dimensionally equal to :