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Units & Dimensions

JEE Main level, single correct, medium

92 of 149

Question 92 of 149

The SI unit of a physical quantity is $Pascal‐\sec$ . The dimensional formula of this quantity will be

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Answer: (C) $M{L}^{-1}{T}^{-1}$

Unit of Pascal is

N{m}^{-2}

.
So, dimension of

Pascal‐\sec

\left[N{m}^{-2}\right]\left[s\right]

=\dfrac{ML{T}^{-2}}{{L}^{2}}\times T=M{L}^{-1}{T}^{-1}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

Units & DimensionsThe dimensional formula of magnetic permeability of free space $\mu_0$ is:
Units & DimensionsA new unit $(\alpha)$ of length is chosen such that it is equal to the speed of light in vacuum. What is the distance between Venus and Earth in terms of $\alpha$ units if light takes $6$ min. $40$ s to cover this distance?
Units & DimensionsKeeping the significant figures in view, the sum of the physical quantities $52.01 \mathrm{~m}, 153.2 \mathrm{~m}$ and 0.123 m is :
Units & DimensionsMatch List-I with List-II.
$\begin{array}{ll} \text{List-I} & \text{List-II} \\ \text{(A) Heat capacity of body} & \text{(I) } \mathrm{J} \mathrm{kg}^{-1} \\ \text{(B) Specific heat capacity of body} & \text{(II) } \mathrm{JK}^{-1} \\ \text{(C) Latent heat} & \text{(III) } \mathrm{J} \mathrm{kg}^{-1} \mathrm{~K}^{-1} \\ \text{(D) Thermal conductivity} & \text{(IV) } \mathrm{Jm}^{-1} \mathrm{~K}^{-1} \mathrm{~s}^{-1} \end{array}$
Choose the correct answer from the options given below :
Units & DimensionsMatch List - I with List - II.

Choose the correct answer from the options given below :
Units & DimensionsMatch List - I with List - II.
$\begin{array}{llll} & \text { List - I } & & \text { List - II } \\ \text { (A) } & \text { Permeability of free space } & \text { (I) }\left[\mathrm{M} \mathrm{~L}^2 \mathrm{~T}^{-2}\right] \\ \text { (B) } & \text { Magnetic field } & \text { (II) }\left[\mathrm{M} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right] \\ \text { (C) } & \text { Magnetic moment } & \text { (III) }\left[\mathrm{M} \mathrm{~L} \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right] \\ \text { (D) } & \text { Torsional constant } & \text { (IV) }\left[\mathrm{L}^2 \mathrm{~A}\right] \end{array}$

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JEE Main Physics practice question on Units & Dimensions (Dimensions), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The SI unit of a physical quantity is Pascal‐sec⁡Pascal‐\secPascal‐sec. The dimensional formula of this quantity will be

JEE Main question paper PDF

More Physics practice

The SI unit of a physical quantity is $Pascal‐\sec$ . The dimensional formula of this quantity will be