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Units & Dimensions

JEE Main level, single correct, medium

100 of 149

Question 100 of 149

If force (F), length (L) and time (T) are taken as the fundamental quantities. Then what will be the dimension of density:

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Answer: (A) $\left[{FL}^{-4}{T}^{2}\right]$

d\propto {F}^{a}{L}^{b}{T}^{c}

\left[M{L}^{-3}\right]={\left[ML{T}^{-2}\right]}^{a}\left[{L}^{b}\right]\left[T{}^{c}\right]

=\left[{M}^{a}{L}^{a+b}{T}^{-2a+c}\right]

comparing :

a=1

......(i)

a+b=-3

....(ii)

-2a+c=0

.......(iii)

c=2;b=-4;∴[d]=\left[{FL}^{-4}{T}^{2}\right]

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Units & Dimensions (Dimensions), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.