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Match List - I with List - II : List-I List-II (a ) h (Planck's constant) (i ) [MLT^-1 ] (b ) E (kinetic energy) (ii ) [ML^2T^-1 ] (c ) V (electric potential) (iii ) [ML^2T^-2 ] (d ) P (linear momentum) (iv ) [ML^2I^-1T^-3 ] Choose the correct answer from the options given below:

(a )→ (ii ), (b )→ (iii ), (c )→ (iv ), (d )→ (i )

(a )→ (i ), (b )→ (ii ), (c )→ (iv ), (d )→ (iii )

(a )→ (iii ), (b )→ (ii ), (c )→ (iv ), (d )→ (i )

(a )→ (iii ), (b )→ (iv ), (c )→ (ii ), (d )→ (i )

Units & Dimensions

JEE Main level, single correct, medium

110 of 149

Question 110 of 149

Match List - I with List - II : $List-I$ $List-II$ $\left(a\right)$ $h$ (Planck's constant) $\left(i\right)$ $\left[{MLT}^{-1}\right]$ $\left(b\right)$ $E$ (kinetic energy) $\left(ii\right)$ $\left[{ML}^{2}{T}^{-1}\right]$ $\left(c\right)$ $V$ (electric potential) $\left(iii\right)$ $\left[{ML}^{2}{T}^{-2}\right]$ $\left(d\right)$ $P$ (linear momentum) $\left(iv\right)$ $\left[{ML}^{2}{I}^{-1}{T}^{-3}\right]$ Choose the correct answer from the options given below:

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Answer: (A) $\left(a\right)\rightarrow \left(ii\right),\left(b\right)\rightarrow \left(iii\right),\left(c\right)\rightarrow \left(iv\right),\left(d\right)\rightarrow \left(i\right)$

By dimensional analysis.

K.E.=\left[{ML}^{2}{T}^{-2}\right]

P

(linear momentum)

=\left[{MLT}^{-1}\right]

h(

planck's constant

)=\left[{ML}^{2}{T}^{-1}\right]

V

(electric potential

)=\left[{ML}^{2}{T}^{-3}{I}^{-1}\right]

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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