Wave Optics

JEE Main level, single correct, medium

157 of 191

Question 157 of 191

Wavelength of light used in an optical instrument are λ1=4000A˚\lambda_1=4000 Å and λ2=5000A˚\lambda_2=5000 Å, then ratio of their respective resolving powers (corresponding to λ1\lambda_1 and λ2\lambda_2 ) is

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Answer: (D) 5 : 4

Resolving power α(1/λ)\alpha(1 / \lambda). Hence, ( R.P )1( R.P )2=λ2λ1=54\frac{(\text { R.P })_1}{(\text { R.P })_2}=\frac{\lambda_2}{\lambda_1}=\frac{5}{4}

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