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Work Energy Power

JEE Main level, numerical answer, medium

107 of 183

Question 107 of 183

Two solids $A$ and $B$ of mass $1kg$ and $2kg$ respectively are moving with equal linear momentum. The ratio of their kinetic energies ${\left(K.E.\right)}_{A}:{\left(K.E.\right)}_{B}$ will be $\dfrac{A}{1},$ so the value of $A$ will be _________.

Show answer and solution

Answer: 2

Kinetic energy

K=\dfrac{{P}^{2}}{2m},\left({P}_{A}={P}_{B}\right)

K\propto \dfrac{1}{m}

\dfrac{{K}_{A}}{{K}_{B}}=\dfrac{{m}_{B}}{{m}_{A}}

=\dfrac{2}{1}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Work Energy Power (Energy), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

Two solids AAA and BBB of mass 1kg1kg1kg and 2kg2kg2kg respectively are moving with equal linear momentum. The ratio of their kinetic energies (K.E.)A:(K.E.)B{\left(K.E.\right)}_{A}:{\left(K.E.\right)}_{B}(K.E.)A​:(K.E.)B​ will be A1,\dfrac{A}{1},1A​, so the value of AAA will be _________.

JEE Main question paper PDF

More Physics practice

Two solids $A$ and $B$ of mass $1kg$ and $2kg$ respectively are moving with equal linear momentum. The ratio of their kinetic energies ${\left(K.E.\right)}_{A}:{\left(K.E.\right)}_{B}$ will be $\dfrac{A}{1},$ so the value of $A$ will be _________.