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Work Energy Power

JEE Main level, single correct, medium

108 of 183

Question 108 of 183

If the potential energy between two molecules is given by $U=\dfrac{A}{{r}^{6}}+\dfrac{B}{{r}^{12}},$ then at equilibrium, separation between molecules, and the potential energy are:

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Answer: (C) ${\left(\dfrac{2B}{A}\right)}^{1/6},\dfrac{{A}^{2}}{4B}$

U=\dfrac{A}{{r}^{6}}+\dfrac{B}{{r}^{12}}

f=-\dfrac{dU}{dr}

For equilibrium

f=0

r={\left(\dfrac{2B}{A}\right)}^{\dfrac{1}{6}}

Then,

U=\dfrac{{A}^{2}}{4B}

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

JEE Main Physics practice question on Work Energy Power (Energy), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

If the potential energy between two molecules is given by U=Ar6+Br12,U=\dfrac{A}{{r}^{6}}+\dfrac{B}{{r}^{12}},U=r6A​+r12B​, then at equilibrium, separation between molecules, and the potential energy are:

JEE Main question paper PDF

More Physics practice

If the potential energy between two molecules is given by $U=\dfrac{A}{{r}^{6}}+\dfrac{B}{{r}^{12}},$ then at equilibrium, separation between molecules, and the potential energy are: