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Statistics & Probability

JEE Main level, single correct, medium

1 of 2

Question 1 of 2

If $P(A) = 0.4$ , $P(B) = 0.8$ , and $P(B|A) = 0.6$ , then $P(A \cup B)$ is:

Show answer and solution

Answer: (A) $0.96$

P(A \cap B) = P(B|A) P(A) = 0.6 \times 0.4 = 0.24

. Then

P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.4 + 0.8 - 0.24 = 0.96

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Mathematics practice

JEE Main Mathematics practice question on Statistics & Probability, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

If P(A)=0.4P(A) = 0.4P(A)=0.4, P(B)=0.8P(B) = 0.8P(B)=0.8, and P(B∣A)=0.6P(B|A) = 0.6P(B∣A)=0.6, then P(A∪B)P(A \cup B)P(A∪B) is:

JEE Main question paper PDF

More Mathematics practice

If $P(A) = 0.4$ , $P(B) = 0.8$ , and $P(B|A) = 0.6$ , then $P(A \cup B)$ is: