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Solve 2x² − 5x − 3 = 0

Concept: Quadratic equation solution

Question

Solve 2x² − 5x − 3 = 0

Try it yourself first

Hint: Can you recall the quadratic formula and identify the coefficients a,b,ca, b, c from the given equation?

Step-by-step solution

  1. 1

    Given equation

    We are given the quadratic equation:
    2x2−5x−3=02x^2 - 5x - 3 = 0
  2. 2

    Quadratic formula

    For ax2+bx+c=0ax^2 + bx + c = 0, the roots are given by the quadratic formula:
    x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
  3. 3

    Identify coefficients

    Compare the given equation with the standard form to identify a,b,ca, b, c:
    a=2,b=−5,c=−3a=2, b=-5, c=-3
  4. 4

    Substitute values

    Substitute these values into the quadratic formula:
    x=−(−5)±(−5)2−4(2)(−3)2(2)x = \frac{-(-5) \pm \sqrt{(-5)^2 - 4(2)(-3)}}{2(2)}
  5. 5

    Simplify discriminant

    Simplify the expression under the square root (the discriminant):
    x=5±25−(−24)4x = \frac{5 \pm \sqrt{25 - (-24)}}{4}
  6. 6

    Further simplification

    Continue simplifying the expression:
    x=5±494x = \frac{5 \pm \sqrt{49}}{4}
  7. 7

    Calculate square root

    Calculate the square root of 49:
    x=5±74x = \frac{5 \pm 7}{4}
  8. 8

    Find two roots

    Separate into two cases to find the two roots:
    x1=5+74,x2=5−74x_1 = \frac{5 + 7}{4}, x_2 = \frac{5 - 7}{4}
  9. 9

    Final roots

    Calculate the values for x1x_1 and x2x_2:
    x1=3,x2=−1/2x_1 = 3, x_2 = -1/2

Final answer

x=3,x=−1/2x = 3, x = -1/2

Remember: Quadratic formula always works for $ax^2+bx+c=0$.

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Quick check · test yourself

Which of the following statements is true about the discriminant (b2−4acb^2 - 4ac) of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0?

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