Mathematics · Class 9-10 · CBSE
Arithmetic Progressions: Formulas, Derivations and Word Problems
Learn arithmetic progressions (AP): common difference d, derivation of the nth term formula an = a + (n-1)d, Gauss derivation of sum of n terms Sn = (n/2)[2a + (n-1)d], and practical word problems.
1Definition and Components of an AP
AnArithmetic Progression (AP)is a sequence of numbers in which each term is obtained by adding a fixed constant number, called theCommon Difference (d), to the preceding term, except the first term (a).
Common Difference Property
Types of Common Difference (d)
| Value of d | Sequence Trend | Example AP Series | Significance |
|---|---|---|---|
| Positive (d > 0) | Strictly increasing sequence | Terms grow progressively larger | |
| Negative (d < 0) | Strictly decreasing sequence | Terms decrease towards negative values | |
| Constant stationary sequence | Every term is identical to the first term |
Positive (d > 0)
- Sequence Trend
- Strictly increasing sequence
- Example AP Series
- Significance
- Terms grow progressively larger
Negative (d < 0)
- Sequence Trend
- Strictly decreasing sequence
- Example AP Series
- Significance
- Terms decrease towards negative values
- Sequence Trend
- Constant stationary sequence
- Example AP Series
- Significance
- Every term is identical to the first term
2The nth Term Formula and Selection of Terms
General nth Term of an AP
- = The nth term (or last term l)
- a = The first term
- n = Position index (must be a positive integer 1, 2, 3...)
- d = Common difference
Clever Selection of Terms in Problem Solving
| Number of Terms | Optimal Symmetric Form | Common Difference | Sum Simplification Benefit |
|---|---|---|---|
| 3 Terms | a - d, a, a + d | d | Sum = 3a (d cancels instantly) |
| 4 Terms | a - 3d, a - d, a + d, a + 3d | 2d | Sum = 4a (d cancels instantly) |
| 5 Terms | a - 2d, a - d, a, a + d, a + 2d | d | Sum = 5a (d cancels instantly) |
3 Terms
- Optimal Symmetric Form
- a - d, a, a + d
- Common Difference
- d
- Sum Simplification Benefit
- Sum = 3a (d cancels instantly)
4 Terms
- Optimal Symmetric Form
- a - 3d, a - d, a + d, a + 3d
- Common Difference
- 2d
- Sum Simplification Benefit
- Sum = 4a (d cancels instantly)
5 Terms
- Optimal Symmetric Form
- a - 2d, a - d, a, a + d, a + 2d
- Common Difference
- d
- Sum Simplification Benefit
- Sum = 5a (d cancels instantly)
3Sum of First n Terms of an AP
Sum of n Terms Formula
Gauss Method for Sum of First n Natural Numbers
- 1
- 2
- 3
3. Add the two equations term-by-term: 2S = (n+1) + (n+1) + ... (n times).
- 4
4. 2S = n(n + 1) ⇒ S = n(n + 1) / 2.
Real-life example · Finding nth Term from Given Sum Formula
If S_n = 3n² + 5n, find a_n:
• a_n = S_n - S_{n-1} = [3n² + 5n] - [3(n - 1)² + 5(n - 1)]
• a_n = 3n² + 5n - [3(n² - 2n + 1) + 5n - 5] = 3n² + 5n - [3n² - n - 2] = 6n + 2.
• First term a₁ = 6(1) + 2 = 8; Common difference d = 6.
4Exam Corner: Tips, Mistakes & Board Questions
High-Yield Board Revision Takeaways
- The relation a_n = S_n - S_{n-1} is valid for all n ≥ 2; for n = 1, a₁ = S₁.
- nth term from the end of an AP with last term l: a_n(end) = l - (n - 1)d.
- If the sum of n terms is quadratic in n (S_n = An² + Bn), the sequence is guaranteed to be an AP with common difference d = 2A.
Exam question · CBSE Class 10 Board
- A.28th term
- B.35th term
- C.34th term
- D.30th term
- First term a = 21; Common difference d = 18 - 21 = -3.
- Let nth term a_n = -81:
- a + (n - 1)d = -81 ⇒ 21 + (n - 1)(-3) = -81.
- n - 1 = -102 / -3 = 34 ⇒ n = 35.
- Correct answer is option B (35th term).
Answer: B. 35th term
Remember
- In an AP, consecutive terms have constant common difference ==d = aₙ - aₙ₋₁==.
- General term formula: ==aₙ = a + (n - 1)d==.
- Sum of first n terms: ==Sₙ = (n/2)[2a + (n - 1)d] = (n/2)[a + l]==.
- Sum of first n natural numbers isn(n + 1) / 2.
Check yourself
Question 1
If the common difference of an AP is 5, then what is the value of a₁₈ - a₁₃?