Mathematics · Class 9-10 · CBSE

Arithmetic Progressions: Formulas, Derivations and Word Problems

Learn arithmetic progressions (AP): common difference d, derivation of the nth term formula an = a + (n-1)d, Gauss derivation of sum of n terms Sn = (n/2)[2a + (n-1)d], and practical word problems.

1Definition and Components of an AP

AnArithmetic Progression (AP)is a sequence of numbers in which each term is obtained by adding a fixed constant number, called theCommon Difference (d), to the preceding term, except the first term (a).

Common Difference Property

d=an−an−1=a2−a1=a3−a2d = a_{n} - a_{n-1} = a_2 - a_1 = a_3 - a_2

Types of Common Difference (d)

  • Positive (d > 0)

    Sequence Trend
    Strictly increasing sequence
    Example AP Series
    3,7,11,15,19...(d=+4)3, 7, 11, 15, 19... (d = +4)
    Significance
    Terms grow progressively larger
  • Negative (d < 0)

    Sequence Trend
    Strictly decreasing sequence
    Example AP Series
    100,90,80,70...(d=−10)100, 90, 80, 70... (d = -10)
    Significance
    Terms decrease towards negative values
  • Zero (d=0)\text{Zero}\ (d = 0)

    Sequence Trend
    Constant stationary sequence
    Example AP Series
    5,5,5,5,5...(d=0)5, 5, 5, 5, 5... (d = 0)
    Significance
    Every term is identical to the first term

2The nth Term Formula and Selection of Terms

General nth Term of an AP

an=a+(n−1)⋅da_n = a + (n - 1) \cdot d
  • ana_n = The nth term (or last term l)
  • a = The first term
  • n = Position index (must be a positive integer 1, 2, 3...)
  • d = Common difference

Clever Selection of Terms in Problem Solving

  • 3 Terms

    Optimal Symmetric Form
    a - d, a, a + d
    Common Difference
    d
    Sum Simplification Benefit
    Sum = 3a (d cancels instantly)
  • 4 Terms

    Optimal Symmetric Form
    a - 3d, a - d, a + d, a + 3d
    Common Difference
    2d
    Sum Simplification Benefit
    Sum = 4a (d cancels instantly)
  • 5 Terms

    Optimal Symmetric Form
    a - 2d, a - d, a, a + d, a + 2d
    Common Difference
    d
    Sum Simplification Benefit
    Sum = 5a (d cancels instantly)

3Sum of First n Terms of an AP

Sum of n Terms Formula

Sn=n2[2a+(n−1)d]=n2[a+l]S_n = \frac{n}{2} \left[ 2a + (n - 1)d \right] = \frac{n}{2} \left[ a + l \right]

Gauss Method for Sum of First n Natural Numbers

  1. 1

    1.Write S=1+2+3+...+n.1. \text{Write}\ S = 1 + 2 + 3 + ... + n.

  2. 2

    2.Write Sinreverse :S=n+(n−1)+...+1.2. \text{Write}\ S in \text{reverse}\ : S = n + (n-1) + ... + 1.

  3. 3

    3. Add the two equations term-by-term: 2S = (n+1) + (n+1) + ... (n times).

  4. 4

    4. 2S = n(n + 1) ⇒ S = n(n + 1) / 2.

Real-life example · Finding nth Term from Given Sum Formula

If S_n = 3n² + 5n, find a_n:
• a_n = S_n - S_{n-1} = [3n² + 5n] - [3(n - 1)² + 5(n - 1)]
• a_n = 3n² + 5n - [3(n² - 2n + 1) + 5n - 5] = 3n² + 5n - [3n² - n - 2] = 6n + 2.
• First term a₁ = 6(1) + 2 = 8; Common difference d = 6.

4Exam Corner: Tips, Mistakes & Board Questions

High-Yield Board Revision Takeaways

  • The relation a_n = S_n - S_{n-1} is valid for all n ≥ 2; for n = 1, a₁ = S₁.
  • nth term from the end of an AP with last term l: a_n(end) = l - (n - 1)d.
  • If the sum of n terms is quadratic in n (S_n = An² + Bn), the sequence is guaranteed to be an AP with common difference d = 2A.

Exam question · CBSE Class 10 Board

Which term of the AP: 21, 18, 15... is -81?
  1. A.28th term
  2. B.35th term
  3. C.34th term
  4. D.30th term

Remember

  • In an AP, consecutive terms have constant common difference ==d = aₙ - aₙ₋₁==.
  • General term formula: ==aₙ = a + (n - 1)d==.
  • Sum of first n terms: ==Sₙ = (n/2)[2a + (n - 1)d] = (n/2)[a + l]==.
  • Sum of first n natural numbers isn(n + 1) / 2.

Check yourself

  1. Question 1

    If the common difference of an AP is 5, then what is the value of a₁₈ - a₁₃?

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