Mathematics · Class 9-10 · CBSE
Real Numbers: Prime Factorisation and Irrationality Proofs
Master the Fundamental Theorem of Arithmetic, prime factorisation method for HCF and LCM, proving the irrationality of √2, √3, and √5 by contradiction, and decimal expansion conditions for rational numbers.
1Fundamental Theorem of Arithmetic and HCF-LCM Relations
TheFundamental Theorem of Arithmeticstates that every composite number can be expressed (factorised) uniquely as a product of prime numbers, apart from the order in which the prime factors occur.
Product Property for Two Positive Integers
Prime Factorisation Definitions: HCF vs LCM
| Concept | Prime Factor Definition | Calculation Procedure | Example for 36 and 84 |
|---|---|---|---|
| HCF (Highest Common Factor) | Product of the SMALLEST power of each common prime factor involved in the numbers | 36 = 2² × 3²; 84 = 2² × 3 × 7. Common primes: 2 (min power 2), 3 (min power 1) | HCF = 2² × 3 = 12 |
| LCM (Lowest Common Multiple) | Product of the GREATEST power of each prime factor involved in the numbers | Highest powers: 2², 3², 7¹ | LCM = 2² × 3² × 7 = 4 × 9 × 7 = 252 |
HCF (Highest Common Factor)
- Prime Factor Definition
- Product of the SMALLEST power of each common prime factor involved in the numbers
- Calculation Procedure
- 36 = 2² × 3²; 84 = 2² × 3 ×
7. Common primes: 2 (min power 2), 3 (min power 1) - Example for 36 and 84
- HCF = 2² × 3 = 12
LCM (Lowest Common Multiple)
- Prime Factor Definition
- Product of the GREATEST power of each prime factor involved in the numbers
- Calculation Procedure
- Highest powers: 2², 3², 7¹
- Example for 36 and 84
- LCM = 2² × 3² × 7 = 4 × 9 × 7 = 252
2Proof of Irrationality by Contradiction
A number isIrrationalif it cannot be written in the form p/q where p, q are integers and q ≠
0. We prove numbers like √2, √3, √5 are irrational using the technique ofProof by Contradiction.
Step-by-Step Proof that √2 is Irrational
- 1
1. Assumption: Assume to the contrary that √2 is rational. Hence √2 = a/b, where a and b are co-prime integers (HCF = 1) and b ≠ 0.
- 2
2. Squaring both sides: 2 = a²/b² ⇒ 2b² = a². Therefore, 2 divides a². By Theorem, if a prime p divides a², then p divides a. Hence 2 divides a.
- 3
3. Substitute a = 2c: 2b² = (2c)² = 4c² ⇒ b² = 2c². This implies 2 divides b²; hence 2 divides b.
- 4
4. Contradiction: 2 divides both a and b. This contradicts our initial premise that a and b are co-prime (have no common factor other than 1).
- 5
5. Conclusion: Our assumption that √2 is rational was false. Therefore, √2 is strictly irrational.
3Decimal Expansions of Rational Numbers
Terminating vs Non-Terminating Recurring Decimals
| Decimal Form | Condition on Denominator q (in simplest p/q form) | Decimal Behavior | Example |
|---|---|---|---|
| Terminating Decimal | Prime factorisation of q is strictly of the form 2ⁿ · 5ᵐ (where n, m are non-negative integers) | Ends after finite digits | 13/80 = 13/(2⁴ × 5¹) = 0.1625 |
| Non-Terminating Repeating | Prime factorisation of q contains prime factors other than 2 and 5 (e.g. 3, 7, 11) | Infinite repeating block of digits | 17/30 = 17/(2 × 3 × 5) = 0.5666... |
Terminating Decimal
- Condition on Denominator q (in simplest p/q form)
- Prime factorisation of q is strictly of the form 2ⁿ · 5ᵐ (where n, m are non-negative integers)
- Decimal Behavior
- Ends after finite digits
- Example
- 13/80 = 13/(2⁴ × 5¹) = 0.1625
Non-Terminating Repeating
- Condition on Denominator q (in simplest p/q form)
- Prime factorisation of q contains prime factors other than 2 and 5 (e.g. 3, 7, 11)
- Decimal Behavior
- Infinite repeating block of digits
- Example
- 17/30 = 17/(2 × 3 × 5) = 0.5666...
4Exam Corner: Tips, Mistakes & Board Questions
Critical Board Exam Takeaways
- The relation HCF(a, b) × LCM(a, b) = a × b holds true ONLY for two numbers; it is FALSE for three or more numbers.
- The sum, difference, product, or quotient of a non-zero rational number and an irrational number is always irrational (e.g. 3 + 2√5 is irrational).
- To find whether p/q terminates, always reduce the fraction to simplest lowest terms first so that p and q are co-prime.
Exam question · CBSE Class 10 Board
- A.22338
- B.21456
- C.23450
- D.20198
- We use the fundamental identity: HCF × LCM = Product of two numbers.
- 9 × LCM = 306 × 657.
- LCM = (306 × 657) / 9 = 34 × 657 = 22338.
- Correct answer is option A (22338).
Answer: A. 22338
Remember
- Every composite number has a uniqueprime factorisation.
- For any two positive integers: ==HCF(a, b) × LCM(a, b) = a × b==.
- Irrationality of is established viacontradiction.
- A rational fraction terminates if and only if ====.
Check yourself
Question 1
After how many decimal places will the decimal expansion of 23 / (2⁴ × 5³) terminate?