Physics · Class 9-10 · CBSE

Sound: Waves, Echo, Ultrasound and the Human Ear

Learn how sound propagates as longitudinal compression-rarefaction waves, speed equation v = fλ, minimum distance for clear echo, ultrasound medical & SONAR applications, and human ear anatomy.

1Nature and Propagation of Sound Waves

Sound is mechanical energy that requires a material medium (solid, liquid, or gas) to travel. It cannot travel through a vacuum. It propagates as aLongitudinal Waveconsisting of alternatingCompressions(regions of high pressure and density) andRarefactions(regions of low pressure and density).

Wave Speed Equation

v=ν⋅λ=λTv = \nu \cdot \lambda = \frac{\lambda}{T}
  • v = Wave velocity in metres/second (m/s)
  • ν (or f) = Frequency in Hertz (Hz) = number of vibrations per second
  • λ = Wavelength in metres (distance between two consecutive compressions)
  • T = Time period of one complete wave cycle (T = 1/f)

Speed of Sound Across Media (at 20°C)

  • Solid

    Typical Material
    Steel / Aluminium
    Speed of Sound (m/s)
    5,000 – 6,420 m/s
    Why Speed Differs?
    High elasticity and densely packed molecules transmit vibrations fastest
  • Liquid

    Typical Material
    Water (fresh / sea)
    Speed of Sound (m/s)
    1,480 – 1,530 m/s
    Why Speed Differs?
    Intermediate elasticity and density
  • Gas

    Typical Material
    Air (at 20°C)
    Speed of Sound (m/s)
    344 m/s
    Why Speed Differs?
    Molecules are far apart, transmission depends on thermal collision rates
  • Vacuum

    Typical Material
    Outer space
    Speed of Sound (m/s)
    0 m/s (Cannot travel)
    Why Speed Differs?
    Sound strictly requires a material medium to propagate

2Reflection of Sound, Echo and Reverberation

The repetition of sound caused by reflection from a large obstacle is called anEcho. The sensation of sound persists in our brain for about0.1 seconds(persistence of hearing).

Derivation of Minimum Distance for Echo in Air

  1. 1

    1. Speed of sound in air at 22°C = 344 m/s.

  2. 2

    2. Minimum time delay needed between original and reflected sound = 0.1 s.

  3. 3

    3. Total distance traveled by sound (to obstacle and back) = Speed × Time = 344 × 0.1 = 34.4 m.

  4. 4

    4. Minimum distance of obstacle from source = 34.4 / 2 = 17.2 metres.

Echo vs Reverberation

  • Definition

    Echo
    Single clear repetition of sound from distant obstacle
    Reverberation
    Persistence of sound due to repeated reflections from walls/ceilings
  • Obstacle Distance

    Echo
    Obstacle must be at least 17.2 m away
    Reverberation
    Occurs in closed halls/auditoriums even when distance < 17 m
  • Clarity of Speech

    Echo
    Clean separation, words are distinct
    Reverberation
    Causes speech blurring; requires sound-absorbent panels

3Ultrasound Applications and Human Ear Anatomy

Sound Frequency Spectrum

  • Infrasound

    Frequency Band
    < 20 Hz
    Detectors / Real-world Examples
    Elephants, rhinoceros, earthquakes, volcanic eruptions
  • Audible Sound

    Frequency Band
    20 Hz – 20,000 Hz
    Detectors / Real-world Examples
    Normal human hearing range
  • Ultrasound

    Frequency Band
    > 20,000 Hz (20 kHz)
    Detectors / Real-world Examples
    Bats, dolphins, echocardiography, SONAR, kidney stone lithotripsy

How the Human Ear Converts Waves to Nerve Impulses

  1. 1

    1. Pinna collects sound waves and channels them down the auditory canal.

  2. 2

    2. Eardrum (tympanum) vibrates upon encountering sound pressure waves.

  3. 3

    3. Three middle ear bones (Hammer, Anvil, Stirrup) amplify the mechanical vibrations by ~20 times.

  4. 4

    4. Cochlea fluid converts mechanical pressure into electrical nerve impulses via hair sensory cells.

  5. 5

    5. Auditory nerve transmits electrical signals to the brain for sound recognition.

4Exam Corner: Tips, Mistakes & Board Questions

High-Frequency Exam Takeaways

  • SONAR (Sound Navigation and Ranging) uses ultrasound pulse echo: 2d = v × t to measure sea depth.
  • Pitch is determined by frequency; Loudness is determined by amplitude of vibration.
  • Reverberation in auditoriums is minimized using sound-absorbing drapes, compressed fibreboards, and curved ceilings.

Exam question · CBSE Class 9/10 Board

A ship sends out an ultrasound pulse that returns from the seabed after 3.2 seconds. If speed of sound in seawater is 1530 m/s, what is the ocean depth?
  1. A.4896 m
  2. B.2448 m
  3. C.1530 m
  4. D.3060 m

Remember

  • Sound is a longitudinal wave needing a material medium; fastest in solids, zero in vacuum.
  • Wave speed equation: ==v = f · λ==.
  • Echo requires a minimum reflection distance of17.2 metresin air.
  • Ultrasound (> 20 kHz) powersSONARand non-invasive medical diagnostics.

Check yourself

  1. Question 1

    Which characteristic of sound allows us to distinguish between two different singers singing the same note at equal loudness?

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