Current Electricity

NEET level, single correct, medium

3 of 380

Question 3 of 380

A wire of resistance RR is stretched to double its original length keeping volume constant. Its new resistance is:

Show answer and solution

Answer: (A) 4R4R

Since V=ALV = A L is constant, when LL doubles, AA halves: R′=ρ(2L)/(A/2)=4RR' = \rho (2L)/(A/2) = 4R.

NEET question paper PDF

The full paper for each year. Open it on this page or download it.

NEET 2025 question paper (Code 45)

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Circuit builder simulationDrag the sliders and watch the numbers in this question change.Revise Current Electricity firstFormula sheet, solved examples and the traps students fall into.

More Physics practice

NEET Physics practice question on Current Electricity, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.