Current Electricity

JEE Main level, single correct, medium

7 of 380

Question 7 of 380

Current passing through a wire as function of time is given as I(t)=0.02t+0.01 A\mathrm{I}(\mathrm{t})=0.02 \mathrm{t}+0.01 \mathrm{~A}. The charge that will flow through the wire from t=1st=1 s to t=2st=2 s is :

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Answer: (D) 0.04 C

q=∫idt∫02(0.02t+0.01)dt\begin{aligned} & \mathrm{q}=\int \mathrm{idt} \\ & \int_0^2(0.02 \mathrm{t}+0.01) \mathrm{dt}\end{aligned}
q=[0.02t22+0.01t]12=0.01(3)+0.01(1)=0.04C\begin{aligned} & \mathrm{q}=\left[0.02 \frac{\mathrm{t}^2}{2}+0.01 \mathrm{t}\right]_1^2 \\ & =0.01(3)+0.01(1) \\ & =0.04 \mathrm{C}\end{aligned}

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