Current Electricity

JEE Main level, numerical answer, medium

8 of 380

Question 8 of 380

The current in a conductor is expressed as I=3t2+4t3I=3{t}^{2}+4{t}^{3}, where II is in Ampere and tt is in second. The amount of electric charge that flows through a section of the conductor during t=1st=1s to t=2st=2s is ____________ C.C.

Show answer and solution

Answer: 22

For variable current, integrate to get the total charge flown in a given interval.q=∫12idt=∫12(3t2+4t3)dtq={\int }_{1}^{2}idt={\int }_{1}^{2}\left(3{t}^{2}+4{t}^{3}\right)dt
⇒q=(t3+t4)12{\Rightarrow q=\left({t}^{3}+{t}^{4}\right)}_{1}^{2}
⇒q=22C\Rightarrow q=22C

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Circuit builder simulationDrag the sliders and watch the numbers in this question change.Revise Current Electricity firstFormula sheet, solved examples and the traps students fall into.

More Physics practice

JEE Main Physics practice question on Current Electricity (Electric Current and Drift of Electrons), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.