Equilibrium

NEET level, single correct, medium

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Question 2 of 2

The pHpH of a 10−8 M10^{-8}\,\text{M} HClHCl solution in water at 25∘C25^\circ\text{C} is:

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Answer: (D) Between 6 and 7

Contribution from auto-ionization of water (10−7 M10^{-7}\,\text{M}) must be added: [H+]=10−8+10−7=1.1×10−7  ⟹  pH≈6.96[H^+] = 10^{-8} + 10^{-7} = 1.1 \times 10^{-7} \implies pH \approx 6.96.

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