Equilibrium

JEE Main level, single correct, medium

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Question 1 of 2

The solubility SS of a sparingly soluble salt AB2AB_2 having solubility product KspK_{sp} is given by:

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Answer: (C) (Ksp/4)1/3(K_{sp}/4)^{1/3}

AB2⇌A2++2B−  ⟹  Ksp=S(2S)2=4S3  ⟹  S=(Ksp/4)1/3AB_2 \rightleftharpoons A^{2+} + 2B^- \implies K_{sp} = S(2S)^2 = 4S^3 \implies S = (K_{sp}/4)^{1/3}.

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