Oscillations

JEE Main level, single correct, medium

1 of 194

Question 1 of 194

A particle executes SHM of amplitude AA. At what displacement xx from mean position is kinetic energy equal to potential energy?

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Answer: (A) A/2A/\sqrt{2}

12k(A2−x2)=12kx2  ⟹  A2−x2=x2  ⟹  2x2=A2  ⟹  x=A2\frac{1}{2} k (A^2 - x^2) = \frac{1}{2} k x^2 \implies A^2 - x^2 = x^2 \implies 2x^2 = A^2 \implies x = \frac{A}{\sqrt{2}}.

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