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Oscillations

NEET level, single correct, medium

2 of 194

Question 2 of 194

The time period of a simple pendulum of length $L$ on the surface of the Moon ( $g_m = g/6$ ) will:

Show answer and solution

Answer: (A) Increase by $\sqrt{6}$ times

T = 2\pi\sqrt{L/g}

. If

g

decreases by factor of 6,

T

increases by

\sqrt{6}

times.

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NEET 2025 question paper (Code 45)

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More Physics practice

OscillationsA particle executes SHM of amplitude $A$ . At what displacement $x$ from mean position is kinetic energy equal to potential energy?
OscillationsA horizontal spring-mass system with $m=2\,\text{kg}$ and $k=200\,\text{N/m}$ oscillates with amplitude $0.1\,\text{m}$ . Maximum speed of mass is:
OscillationsA particle is executing simple harmonic motion. Its amplitude is $A$ and time period is $5$ sec. The time required by it to move from $x = A$ to $x = \dfrac{A}{\sqrt{2}}$ is _______ sec.
OscillationsMatch List-I with List-II.
List-IList-IIA. $\sin^2 \omega t$ I. Periodic with time period $T = \dfrac{\pi}{\omega}$ but not simple harmonic motion (SHM)B. $\sin^3(2\omega t)$ II. Periodic with time period $T = \dfrac{2\pi}{\omega}$ but Not SHMC. $\sin(\omega t) + \cos(\pi \omega t)$ III. Periodic with time period $T = \dfrac{\pi}{\omega}$ and SHMD. $\cos\omega t + \cos 2\omega t$ IV. Non-periodic
Choose the correct answer from the options given below :
OscillationsThe velocity of a particle executing simple harmonic motion along $x$ -axis is described as $v^2 = 50 - x^2$ , where $x$ represents displacement. If the time period of motion is $\dfrac{x}{7}$ s, the value of $x$ is _____.
OscillationsThe equation of motion of a particle is given by $x = a \sin\left(50t + \dfrac{\pi}{3}\right)$ cm. The particle will come to rest at time $t_1$ and it will have zero acceleration at time $t_2$ . The $t_1$ and $t_2$ respectively are _______.

NEET Physics practice question on Oscillations, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The time period of a simple pendulum of length LLL on the surface of the Moon (gm=g/6g_m = g/6gm​=g/6) will:

NEET question paper PDF

More Physics practice

The time period of a simple pendulum of length $L$ on the surface of the Moon ( $g_m = g/6$ ) will: