Atoms & Nuclei

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49 of 239

Question 49 of 239

The angular momentum for the electron in Bohr’s orbit is LL. If the electron is assumed to revolve in second orbit of hydrogen atom, then the change in angular momentum will be

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Answer: (C) LL

Bohr's formula for angular momentum of an electron in an orbit is given by
L=nh2πL=\dfrac{nh}{2\pi }
For the first orbit, n=1n=1 and the angular momentum is L1=h2π=L{L}_{1}=\dfrac{h}{2\pi }=L
For 2nd{2}^{nd} orbit
L2=2h2π=2L{L}_{2}=\dfrac{2h}{2\pi }=2L
Hence, the change in angular momentum is
ΔL=2L−L=L\Delta L=2L-L=L

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