Atoms & Nuclei

JEE Main level, single correct, medium

58 of 239

Question 58 of 239

The momentum of an electron revolving in nth{n}^{th} orbit is given by : (Symbols have their usual meanings)

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Answer: (A) nh2πr\dfrac{nh}{2\pi r}

According to Bohr's postulates, angular momentum of an electron in an orbit is given by,
L=mvr=nh2πL=mvr=\dfrac{nh}{2\pi }
Therefore, linear momentum p=Lr=nh2πrp=\dfrac{L}{r}=\dfrac{nh}{2\pi r}

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