Question 44 of 130

Three point particles of masses $1.0kg,1.5kg$ and $2.5kg$ are placed at three corners of a right angle triangle of sides $4.0cm,3.0cm$ and $5.0cm$ as shown in the figure. The centre of mass of the system is at a point:

A$0.6cm$ right and $2.0cm$ above $1kg$ mass.B$1.5cm$ right and $1.2cm$ above $1kg$ mass.C$2.0cm$ right and $0.9cm$ above $1kg$ mass.D$0.9cm$ right and $2.0cm$ above $1kg$ mass.

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Answer: (D) $0.9cm$ right and $2.0cm$ above $1kg$ mass.

Take $1kg$ mass at origin

${X}_{cm}=\dfrac{1\times 0+1.5\times 3+2.5\times 0}{5}=0.9cm$
${Y}_{cm}=\dfrac{1\times 0+1.5\times 0+2.5\times 4}{5}=2cm$