Center of Mass, Momentum & Collision

JEE Main level, single correct, medium

48 of 130

Question 48 of 130

Consider a circular disc of radius 20 cm with centre located at the origin. A circular hole of radius 5 cm is cut from this disc in such a way that the edge of the hole touches the edge of the disc. The distance of centre of mass of residual or remaining disc from the origin will be

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Answer: (C) 1.0 cm



 mass of disc =m\text { mass of disc }=\mathrm{m}
 mass of cut part =m16\text { mass of cut part }=\frac{m}{16}
Xcom=m×0−m16×15m−m16X_{c o m}=\frac{m \times 0-\frac{m}{16} \times 15}{m-\frac{m}{16}}
=1 cm.=1 \mathrm{~cm} .

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