Center of Mass, Momentum & Collision

JEE Main level, numerical answer, medium

51 of 130

Question 51 of 130

The position of the centre of mass of a uniform semi-circular wire of radius RR placed in x−yx-y plane with its centre at the origin and the line joining its ends as x−x-axis is given by, (0,xRπ).\left(0,\dfrac{xR}{\pi }\right). Then, the value of ∣x∣|x| is ..

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Answer: 2

COM of semi-circular ring is at 2Rπ\dfrac{2R}{\pi }

Distance from centre ⇒x=2\Rightarrow x=2

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