Center of Mass, Momentum & Collision

JEE Main level, single correct, medium

64 of 130

Question 64 of 130

A thin rod of length ' LL ' is lying along the xx-axis with its ends at x=0x=0 and x=Lx=L. Its linear density (mass/length) varies with xx ask (xL)n\left(\frac{x}{L}\right)^n, where nn can be zero or any positive number. If the position xCMx_{\mathrm{CM}} of the centre of mass of the rod is plotted against ' nn ', which of the following graphs best approximates the dependence of xCMx_{\mathrm{CM}} on nn ?

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Answer: (A)

xcm=∫dmx∫dm=∫λdx⋅x∫dm=∫k(xL)n⋅xdx∫k(xL)ndx=[kxn+2(n+2)Lnkxn+1(n+1)Ln]0L=[x(n+1)n+2]0Lxcm=L2,2L3,3L4,4L5,5L6,…\begin{aligned} & x_{c m}=\frac{\int d m x}{\int d m}=\frac{\int \lambda d x \cdot x}{\int d m}=\frac{\int k\left(\frac{x}{L}\right)^n \cdot x d x}{\int k\left(\frac{x}{L}\right)^n d x}=\left[\frac{\frac{k x^{n+2}}{(n+2) L^n}}{\frac{k x^{n+1}}{(n+1) L^n}}\right]_0^L=\left[\frac{x(n+1)}{n+2}\right]_0^L \\ & x_{c m}=\frac{L}{2}, \frac{2 L}{3}, \frac{3 L}{4}, \frac{4 L}{5}, \frac{5 L}{6}, \ldots \end{aligned}

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