Center of Mass, Momentum & Collision

JEE Main level, numerical answer, medium

79 of 130

Question 79 of 130

A batsman hits back a ball of mass 0.4kg0.4kg straight in the direction of the bowler without changing its initial speed of 15ms−115{ms}^{-1}. The impulse imparted to the ball is _____ NsNs.

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Answer: 12


Impulse, J=∫Fdt=J=\int Fdt=Change in momentum
Therefore,
Impulse, Δp=mv−(−mv)=2mv=2×0.4×15=12Ns\Delta p=mv-\left(-mv\right)=2mv=2\times 0.4\times 15=12Ns

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