Center of Mass, Momentum & Collision

JEE Main level, single correct, medium

120 of 130

Question 120 of 130

The mass of a hydrogen molecule is 3.32×10−27kg.3.32\times {10}^{-27}kg. If 1023{10}^{23} hydrogen molecules strike, per second, a fixed wall of the area 2cm22{cm}^{2} at an angle of 45o{45}^{o} to the normal, and rebound elastically with a speed of 103ms−1,{10}^{3}m{s}^{-1}, then the pressure on the wall is nearly:

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Answer: (B) 2.35×103Nm−22.35\times {10}^{3}N{m}^{-2}



F=2mnVcosθF=2mnVcos\theta⇒P=2mnVcosθA\Rightarrow P=\dfrac{2mnVcos\theta }{A}

⇒P=2×3.32×10−27×1023×1032×2×10−4\Rightarrow P=\dfrac{2\times 3.32\times {10}^{-27}\times {10}^{23}\times {10}^{3}}{\sqrt{2}\times 2\times {10}^{-4}}

⇒P=2.35×103Nm−2\Rightarrow P=2.35\times {10}^{3}N{m}^{-2}

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