Question 20 of 380

The total current supplied to the circuit as shown in figure by the $5V$ battery is _____ $A$.

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Answer: 2

As in this case, $5\Omega$ & $5\Omega$ are in parallel hence, their combined resistance value will be $2.5\Omega$. Now, this $2.5\Omega$ with existing $2.5\Omega$ are in series and hence can be combined to write $5\Omega$.

In the final diagram, we can write equivalent resistance across the battery as $2.5\Omega$.

Hence, current through the battery is, $i=\dfrac{5V}{2.5\Omega }=2A$

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