Current Electricity

JEE Main level, single correct, medium

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Question 37 of 380

A generator has armature resistance of 0.1Ω0.1 \Omega and develops an induced emf of 120 V120 \mathrm{~V} when driven at its rated speed. Its terminal voltage when a current of 50 A50 \mathrm{~A} is being drawn is

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Answer: (C) 115 V115 \mathrm{~V}

Armature resistance R=0.1ΩR=0.1 \Omega
Induced emf, e=120 Ve=120 \mathrm{~V}
Current drown, I=50 AI=50 \mathrm{~A}
We know that,
e=V+IRe=V+I R
or, V=e−IR=120−50×0.1=115 VV=e-I R=120-50 \times 0.1=115 \mathrm{~V}

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