Question 44 of 380

A wire of length 25 m and cross-sectional area $5 \mathrm{~mm}^2$ having resistivity of $2 \times 10^{-6} \Omega \mathrm{~m}$ is bent into a complete circle. The resistance between diametrically opposite points will be

A$12.5 \Omega$B$50 \Omega$C$100 \Omega$D$25 \Omega$

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Answer: (D) $25 \Omega$

$\begin{aligned}
& \mathrm{L}=25 \mathrm{~m}, \mathrm{~A}=5 \mathrm{~mm}^2=5 \times 10^{-6} \mathrm{~m}^2 \\
& \rho=2 \times 10^{-6} \Omega \mathrm{~m} \\
& \mathrm{R}_{\text {wire }}=\frac{\rho \mathrm{L}}{\mathrm{~A}}=\frac{2 \times 10^{-6} \times 25}{5 \times 10^{-6}}=10 \\
& \mathrm{R}_{\mathrm{eq}}=\frac{\mathrm{R}}{4}=\frac{10}{4}=2.5 \Omega
\end{aligned}$
Answer does not match with NTA option.