Current Electricity

JEE Main level, single correct, medium

88 of 380

Question 88 of 380

The resistance of a bulb filament is 100Ω100 \Omega at a temperature of 100∘C100^{\circ} \mathrm{C}. If its temperature coefficient of resistance be 0.0050.005 per ∘C{ }^{\circ} \mathrm{C}, its resistance will become 200Ω200 \Omega at a temperature of

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Answer: (B) 300∘C300^{\circ} \mathrm{C}

200=100[1+(0.005×Δt)]200=100[1+(0.005 \times \Delta t)]
T−100=200T-100=200
T=300∘C\mathrm{T}=300^{\circ} \mathrm{C}

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