Question 106 of 380
In the given figure and . Battery is ideal with emf . Equivalent resistant of the circuit and current supplied by battery are respectively :
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Answer: (B) and
Here are in parallel
$\begin{aligned}
& \frac{1}{\mathrm{R}_{234}}=\frac{1}{\mathrm{R}_2}+\frac{1}{\mathrm{R}_3}+\frac{1}{\mathrm{R}_4} \\
& \mathrm{R}_{234}=2 \Omega
\end{aligned}$
is in series with so
$\begin{aligned}
& \mathrm{R}_{\mathrm{eq}}=\mathrm{R}_{234}+\mathrm{R}_1=2+10=12 \Omega \\
& \mathrm{i}=\frac{12}{12}=1 \mathrm{Amp}
\end{aligned}$
$\begin{aligned}
& \frac{1}{\mathrm{R}_{234}}=\frac{1}{\mathrm{R}_2}+\frac{1}{\mathrm{R}_3}+\frac{1}{\mathrm{R}_4} \\
& \mathrm{R}_{234}=2 \Omega
\end{aligned}$
is in series with so
$\begin{aligned}
& \mathrm{R}_{\mathrm{eq}}=\mathrm{R}_{234}+\mathrm{R}_1=2+10=12 \Omega \\
& \mathrm{i}=\frac{12}{12}=1 \mathrm{Amp}
\end{aligned}$
%2010.5%20%CE%A9%20and%201.14%20~A%0A(B)%2012%20%CE%A9%20and%201%20~A%0A(C)%2010.5%20%CE%A9%20and%201%20~A%0A(D)%2012%20%CE%A9%20and%2011.4%20~A){kind=link}