Question 114 of 380

In the given circuit the value of $\left|\dfrac{{I}_{1}+{I}_{3}}{{I}_{2}}\right|$ is:

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Answer: 2

Potential distribution at each point in the circuit is shown in above diagram.
Since, both $10\Omega$ resistors are maintained at same potential difference, so current will be same, thus, using Ohm's law, ${I}_{1}={I}_{2}=\dfrac{20-10}{10}=1A$
Now, current ${I}_{3}=\dfrac{10}{10}=1A$
Hence, the value of $\left|\dfrac{{I}_{1}+{I}_{3}}{{I}_{2}}\right|=\dfrac{1+1}{1}=2$.

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