Question 117 of 380

If the potential difference between $B$ and $D$ is zero, the value of $x$ is $\dfrac{1}{n}\Omega$. The value of $n$ is ______.

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Answer: 2

As potential difference between B & D is zero therefore it is a balanced wheatstone bridge. So, we can write
$\Rightarrow \dfrac{{R}_{1}}{{R}_{2}}=\dfrac{{R}_{3}}{{R}_{4}} \Rightarrow \dfrac{\left(\dfrac{6\times 3}{6+3}\right)}{1+2}=\dfrac{\left(\dfrac{x\times 1}{x+1}\right)}{x}$
$\Rightarrow \dfrac{2}{3}=\dfrac{1}{x+1}$
$\Rightarrow x=0.5=\dfrac{1}{2}$
Hence, required $n=2$.

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