Question 125 of 380

A current of $15mA$ flows in the circuit as shown in figure. The value of potential difference between the points $A$ and $B$ will be

A$50V$B$75V$C$150V$D$275V$

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Answer: (D) $275V$

Using current division rule,
Current, ${i}_{1}=\dfrac{5}{10+5}\times 15mA=5mA$
Now, using Kirchhoff's voltage law- in lower loop,
${V}_{A}-5i-10{i}_{1}-10i={V}_{B}$
Potential difference between $A$ and $B$ is ${V}_{A}-{V}_{B}=75+50+150=275V$

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