Question 131 of 380

Find the equivalent resistance between point $A$ and $B$

A$65\Omega$B$20\Omega$C$5\Omega$D$2\Omega$

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Answer: (C) $5\Omega$

Therefore, ${R}_{AB}=\dfrac{\left({R}_{AS}+5\right)\times 10}{\left({R}_{AS}+5\right)+10}=\dfrac{\left(5+5\right)\times 10}{\left(5+5\right)+10}=5\Omega$

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