Question 134 of 380

What will be the most suitable combination of three resistors $A=2\Omega ,B=4\Omega ,C=6\Omega$ so that $\left(\dfrac{22}{3}\right)\Omega$ is equivalent resistance of combination?

AParallel combination of $A$ and $C$ connected in series with $B$BParallel combination of $A$ and $B$ connected in series with $C$CSeries combination of $A$ and $C$ connected in parallel with $B$.DSeries combination of $B$ and $C$ connected in parallel with $A$.

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Answer: (B) Parallel combination of $A$ and $B$ connected in series with $C$

If the $2\Omega$ resistance and the $4\Omega$ resistance are connected in parallel to each other, then ${R}^{'}=\dfrac{4\times 2}{4+2}=\dfrac{4}{3}\Omega$. If the resistance of $6\Omega$ is now connected in series to the previous combination.
${R}_{eq}=\dfrac{2\times 4}{2+4}+6=\dfrac{22}{3}\Omega$