Current Electricity

JEE Main level, numerical answer, medium

140 of 380

Question 140 of 380

The voltage across the 10Ω10\Omega resistor in the given circuit is xx volt.

The value of xx to the nearest integer is _____.

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Answer: 70

Req1=50×2070=1007{R}_{e{q}_{1}}=\dfrac{50\times 20}{70}=\dfrac{100}{7}

Req=1707{R}_{eq}=\dfrac{170}{7}
v1=[1701707]×10=70V{v}_{1}=\left[\dfrac{\dfrac{170}{170}}{7}\right]\times 10=70V
=70.00=70.00

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