Current Electricity

JEE Main level, single correct, medium

150 of 380

Question 150 of 380

The resistive network shown below is connected to a D.C.D.C. source of 16V.16V. The power consumed by the network is 44 Watt. The value of RR is:

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Answer: (B) 8Ω8\Omega

Req{R}_{eq} for mixed series and parallel combination of
given circuit Req=114R+14R+R+116R+112R+R{R}_{eq}=\dfrac{1}{\dfrac{1}{4R}+\dfrac{1}{4R}}+R+\dfrac{1}{\dfrac{1}{6R}+\dfrac{1}{12R}}+R
Req=8R{R}_{eq}=8R
Power dissipated by circuit P=V2ReqP=\dfrac{{V}^{2}}{{R}_{eq}}
⇒4=1628R\Rightarrow 4=\dfrac{{16}^{2}}{8R}
⇒R=25632=8Ω\Rightarrow R=\dfrac{256}{32}=8 \Omega

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