Question 152 of 380

Determine the charge on the capacitor in the following circuit:

A$2\mu C$B$60\mu C$C$10\mu C$D$200\mu C$

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Answer: (D) $200\mu C$

After a long time capacitor branch will behave like open circuit so circuit will be like,

Equivalent resistance is
$R=6+\left(4||\left(2+10\right)\right)\Omega =9\Omega$
and, the current through battery becomes $\dfrac{72}{9}=8A$
From the circuit shown, current through $10\Omega$ resistor becomes, $\dfrac{4}{(10+2+4)}\times 8=2A$
Potential available for capacitor is = potential drop across $10\Omega$
$∴$ Potential available for capacitor is: $10\times 2=20V$
$∴$ Charge on capacitor $Q=\left(10\mu F\right)\left(20V\right)=200\mu C$

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