Question 175 of 380

Two cells are connected in opposition as shown. Cell ${E}_{1}$ is of $8V$ emf and $2\Omega$ internal resistance; the cell ${E}_{2}$ is of $2V$ emf and $4\Omega$ internal resistance. The terminal potential difference of cell ${E}_{2}$ is ______ $V$.

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Answer: 6

Current in circuit, $I=\dfrac{8-2}{2+4}=\dfrac{6}{6}=1A$
Applying Kirchhoff's law from $C$ to $B$,
${V}_{C}-2-4\times 1={V}_{B}$
$\Rightarrow {V}_{C}-{V}_{B}=6V$