Question 177 of 380

In the circuit diagram shown in figure given below, the current flowing through resistance $3\Omega$ is $\dfrac{x}{3}A$. The value of $x$ is ________.

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Answer: 1

Let the current flowing through the circuit be $IA$ in anti-clockwise direction.
The net resistance is $R=4.5\Omega +2\Omega +1.5\Omega =8\Omega$
Hence, $I=\dfrac{V}{R}=\dfrac{4V}{8\Omega }=0.5A$

The current flowing through the $3\Omega$ resistor is
$\dfrac{6}{6+3}\times 0.5=\dfrac{1}{3}A$
So, $x=1$

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