Current Electricity

JEE Main level, single correct, medium

220 of 380

Question 220 of 380

When the switch S,S, in the circuit shown, is closed, then the value of current ii will be:

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Answer: (B) 5A5A



i=i2+i2i={i}_{2}+{i}_{2}

V−02=20−V2+10−V4\dfrac{V-0}{2}=\dfrac{20-V}{2}+\dfrac{10-V}{4}

2V+V−10+2(V−20)=02V+V-10+2(V-20)=0

5V−50=05V-50=0

V=10VV=10V

i=102=5Ai=\dfrac{10}{2}=5A

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