Current Electricity

JEE Main level, single correct, medium

225 of 380

Question 225 of 380

There are ' nn ' number of identical electric bulbs, each is designed to draw a power pp independently from the mains supply. They are now joined in series across the main supply. The total power drawn by the combination is :

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Answer: (C) pn\frac{\mathrm{p}}{\mathrm{n}}

Rs=R1+R2+R3+……..+RnV2Ps=V2P+V2P+…….+V2PnPs=Pn\begin{aligned} & R_s=R_1+R_2+R_3+\ldots \ldots..+R_n \\ & \frac{V^2}{P_s}=\frac{V^2}{P}+\frac{V^2}{P}+\ldots \ldots.+\frac{V^2}{P_n} \\ & P_s=\frac{P}{n}\end{aligned}

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