Question 231 of 380

The ratio of heat dissipated per second through the resistance $5 \Omega$ and $10 \Omega$ in the circuit given below is :

A$1: 2$B$2: 1$C$4: 1$D$1: 1$

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Answer: (B) $2: 1$

$\begin{aligned} & \frac{\mathrm{i}_1}{\mathrm{i}_2}=\frac{10}{5}=\frac{2}{1} \\ & \frac{\mathrm{P}_1}{\mathrm{P}_2}=\frac{\mathrm{i}_1^2 \mathrm{R}_1}{\mathrm{i}_2^2 \mathrm{R}_2}=\left(\frac{2}{1}\right)^2 \times \frac{5}{10}=\frac{2}{1}\end{aligned}$

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