Question 233 of 380

In the following circuit, the battery has an emf of $2V$ and an internal resistance of $\dfrac{2}{3}\Omega$. The power consumption in the entire circuit is ______ $W$.

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Answer: 3

As we can see, two resistances of $2\Omega$ in the middle portion(in both left and right side) are in parallel, so their combined resistance will be $\dfrac{2\times 2}{2+2}+\dfrac{2\times 2}{2+2}=2\Omega$. Now this resistance along with the topmost & bottommost resistance are in parallel again, so total resistance of the circuit will be,
${R}_{eq}=\dfrac{2}{3}+\dfrac{2}{3}=\dfrac{4}{3}\Omega$
$∴P=\dfrac{{V}^{2}}{{R}_{eq}}=\dfrac{4}{\dfrac{4}{3}}=3W$

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