Current Electricity

JEE Main level, single correct, medium

249 of 380

Question 249 of 380

A resistor develops 500J500J of thermal energy in 20s20s when a current of 1.5A1.5A is passed through it. If the current is increased from 1.5A1.5A to 3A3A, what will be the energy developed in 20s20s.

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Answer: (D) 2000J2000J

500=(1.5)2×R×20500={\left(1.5\right)}^{2}\times R\times 20
E=(3)2×R×20E={\left(3\right)}^{2}\times R\times 20
E=2000JE=2000J

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