Question 296 of 380

The value of current ${i}_{1}$ flowing from $A$ to $C$ in the circuit diagram is :

A$5A$B$2.25A$C$0.75A$D$1A$

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Answer: (D) $1A$

The Diagram shown in the question represents the balanced wheatstone bridge. It satisfy the condition of balanced wheat stone bridge.
Multiplication of dimensionally opposite resistance is same.
$2\times 2=2\times 2\Rightarrow 4=4$
When the circuit is balanced wheat stone bridge then current through the branch $BD$ is zero, so it can be removed.
Now, after removing $BD$ wire voltage across $AC$ is $8V$.
So, current will be,
${i}_{2}=\dfrac{8}{4+4}=1A$

JEE Main Physics practice question on Current Electricity (Wheatstone Bridge), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.